What is the integral of (2x-3)cos(x^2-3x) ?

The integral of (2x-3)cos(x^2-3x) is sin(x^2-3x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (2x-3)cos(x^2-3x)

\int (2 x - 3) cos (x^{2} - 3 x) d x

sin (x^{2} - 3 x) + C

Solution steps

\int (2 x - 3) cos (x^{2} - 3 x) d x

Apply u-substitution

: \int cos (u) d u

= \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= sin (u)

Substitute back

u = x^{2} - 3 x

= sin (x^{2} - 3 x)

Add a constant to the solution

= sin (x^{2} - 3 x) + C

\int e^{- 2 b x} d x

\int + 7 z^{3} e^{z} d z

\int ln (x) (5 x + 3) d x

\int \frac{x + 2}{x ^{3} + x} d x

What is the integral of (2x-3)cos(x^2-3x) ?
The integral of (2x-3)cos(x^2-3x) is sin(x^2-3x)+C