What is the derivative of (3-17x^2/(3x^3)) ?

The derivative of (3-17x^2/(3x^3)) is -(-17x^2+9)/(3x^4)

What is the first derivative of (3-17x^2/(3x^3)) ?

The first derivative of (3-17x^2/(3x^3)) is -(-17x^2+9)/(3x^4)

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\frac{d}{d x} (\frac{3 - 17 x ^{2}}{3 x ^{3}})

- \frac{- 17 x ^{2} + 9}{3 x ^{4}}

Solution steps

\frac{d}{d x} (\frac{3 - 17 x ^{2}}{3 x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{3} \frac{d}{d x} (\frac{3 - 17 x ^{2}}{x ^{3}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{3} \cdot \frac{\frac{d}{d x} ( 3 - 17 x ^{2} ) x ^{3} - \frac{d}{d x} ( x ^{3} ) ( 3 - 17 x ^{2} )}{( x ^{3} ) ^{2}}

\frac{d}{d x} (3 - 17 x^{2}) = - 34 x

\frac{d}{d x} (x^{3}) = 3 x^{2}

= \frac{1}{3} \cdot \frac{( - 34 x ) x ^{3} - 3 x ^{2} ( 3 - 17 x ^{2} )}{( x ^{3} ) ^{2}}

Simplify

\frac{1}{3} \cdot \frac{( - 34 x ) x ^{3} - 3 x ^{2} ( 3 - 17 x ^{2} )}{( x ^{3} ) ^{2}} : - \frac{- 17 x ^{2} + 9}{3 x ^{4}}

= - \frac{- 17 x ^{2} + 9}{3 x ^{4}}

5 e^{x} tan (x)

\int \frac{4 x ^{2} + 3 x - 1}{x ^{3} - x ^{2}} d x

\frac{\partial}{\partial y} (\frac{y}{x + z})

\int \frac{2 x + 1}{x + 1} d x

f (x) = \frac{3}{x ^{2}}

What is the derivative of (3-17x^2/(3x^3)) ?
The derivative of (3-17x^2/(3x^3)) is -(-17x^2+9)/(3x^4)
What is the first derivative of (3-17x^2/(3x^3)) ?
The first derivative of (3-17x^2/(3x^3)) is -(-17x^2+9)/(3x^4)