What is the integral of 6x^2-4x+7 ?

The integral of 6x^2-4x+7 is 2x^3-2x^2+7x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 6x^2-4x+7

\int 6 x^{2} - 4 x + 7 d x

2 x^{3} - 2 x^{2} + 7 x + C

Solution steps

\int 6 x^{2} - 4 x + 7 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 6 x^{2} d x - \int 4 x d x + \int 7 d x

\int 6 x^{2} d x = 2 x^{3}

\int 4 x d x = 2 x^{2}

\int 7 d x = 7 x

= 2 x^{3} - 2 x^{2} + 7 x

Add a constant to the solution

= 2 x^{3} - 2 x^{2} + 7 x + C

\int \frac{k}{2 x ^{2}} d x

\int sin^{4} (r) cos^{3} (r) d r

\int - \frac{5}{( x ^{2} + 5 ) ^{\frac{3}{2}}} d x

\int \frac{( x ^{2} - a ^{2} ) ^{4}}{x ^{2}} d x

\int 7^{4 x + 1} d x