What is (\partial)/(\partial z)(2xz^2) ?

The answer to (\partial)/(\partial z)(2xz^2) is 4xz

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(\partial)/(\partial z)(2xz^2)

\frac{\partial}{\partial z} (2 x z^{2})

4 x z

Solution steps

\frac{\partial}{\partial z} (2 x z^{2})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 x \frac{\partial}{\partial z} (z^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 x \cdot 2 z^{2 - 1}

Simplify

= 4 x z

x \to \infty lim (x^{a})

y = 2 x - 2 x^{2}, at x = - 1.5

y = (x + 1)^{x^{2}}, (0, 1)

\int \frac{3}{3 x + 2} d x

\int_{1}^{2} (x^{3}) d x

What is (\partial)/(\partial z)(2xz^2) ?
The answer to (\partial)/(\partial z)(2xz^2) is 4xz