What is the integral from-infinity to 1 of 4^{5x-3} ?

The integral from-infinity to 1 of 4^{5x-3} is 8/(5ln(2))

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integral from-infinity to 1 of 4^{5x-3}

\int_{- \infty}^{1} 4^{5 x - 3} d x

\frac{8}{5 ln ( 2 )}

Decimal Notation

2.30831 \dots

Solution steps

\int_{- \infty}^{1} 4^{5 x - 3} d x

Compute the indefinite integral:

\int 4^{5 x - 3} d x = \frac{2 ^{10 x - 7}}{5 ln ( 2 )} + C

Compute the boundaries:

\int_{- \infty}^{1} 4^{5 x - 3} d x = \frac{8}{5 ln ( 2 )} - 0

= \frac{8}{5 ln ( 2 )} - 0

Simplify

= \frac{8}{5 ln ( 2 )}

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What is the integral from-infinity to 1 of 4^{5x-3} ?
The integral from-infinity to 1 of 4^{5x-3} is 8/(5ln(2))