What is the tangent of y=2sin(x),(pi/6 ,1) ?

The tangent of y=2sin(x),(pi/6 ,1) is y=sqrt(3)x+1-pi/(2sqrt(3))

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tangent of y=2sin(x),(pi/6 ,1)

tangent of

y = 2 sin (x), (\frac{π}{6}, 1)

y = 3 x + 1 - \frac{π}{2 3}

Solution steps

Find the slope of

y = 2 sin (x) : \frac{d y}{d x} = 2 cos (x)

Compute the slope of

y = 2 sin (x)

(\frac{π}{6}, 1) : m = 3

Find the line with slope m=

3

and passing through

(\frac{π}{6}, 1) : y = 3 x + 1 - \frac{π}{2 3}

y = 3 x + 1 - \frac{π}{2 3}

x \to 2 + lim (\frac{x ^{2}}{x ^{2} - 4})

1 - (1 - 0.01 x)^{3}

\int_{0}^{1} 11 x x^{2} + 16 d x

x = \frac{1}{2} y^{2} - 3, x = y + 1

f (x) = x + 6

What is the tangent of y=2sin(x),(pi/6 ,1) ?
The tangent of y=2sin(x),(pi/6 ,1) is y=sqrt(3)x+1-pi/(2sqrt(3))