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Popular >

integral from 0 to 4 of (x^3-7x)

Solution

\int_{0}^{4} (x^{3} - 7 x) d x

Solution

8

Solution steps

\int_{0}^{4} x^{3} - 7 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} x^{3} d x - \int_{0}^{4} 7 x d x

\int_{0}^{4} x^{3} d x = 64

\int_{0}^{4} 7 x d x = 56

= 64 - 56

Simplify

= 8

Popular Examples

integral from-3 to 4 of (cos(x)-3/(x^5))

\int_{- 3}^{4} (cos (x) - \frac{3}{x ^{5}}) d x

integral from 2 to 3 of (2x^2)/(x^2-1)

\int_{2}^{3} \frac{2 x ^{2}}{x ^{2} - 1} d x

integral from 0 to 1 of e^{1-x}cos(2x)

\int_{0}^{1} e^{1 - x} cos (2 x) d x

integral from-1 to 1 of (8x)/(x^2+4)

\int_{- 1}^{1} \frac{8 x}{x ^{2} + 4} d x

integral from 1 to 13 of (6x^2+3x-2)

\int_{1}^{13} (6 x^{2} + 3 x - 2) d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of (x^3-7x) ?
The integral from 0 to 4 of (x^3-7x) is 8