What is the integral from-infinity to-1 of θe^θ ?

The integral from-infinity to-1 of θe^θ is -2/e

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integral from-infinity to-1 of θe^θ

\int_{- \infty}^{- 1} θ e^{θ} d θ

- \frac{2}{e}

Decimal Notation

- 0.73575 \dots

Solution steps

\int_{- \infty}^{- 1} θ e^{θ} d θ

Compute the indefinite integral:

\int θ e^{θ} d θ = e^{θ} θ - e^{θ} + C

Compute the boundaries:

\int_{- \infty}^{- 1} θ e^{θ} d θ = - \frac{2}{e} - 0

= - \frac{2}{e} - 0

Simplify

= - \frac{2}{e}

\int_{0}^{1} (π x) d x

\int_{0}^{1} \frac{1 - x}{x} d x

\int_{\frac{2 π}{3}}^{π} cos (\frac{x}{2}) d x

\int_{0}^{\infty} x e^{- 6 x} d x

What is the integral from-infinity to-1 of θe^θ ?
The integral from-infinity to-1 of θe^θ is -2/e