What is the integral from-1 to 1 of (6y^2-5y^4) ?

The integral from-1 to 1 of (6y^2-5y^4) is 2

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integral from-1 to 1 of (6y^2-5y^4)

\int_{- 1}^{1} (6 y^{2} - 5 y^{4}) d y

2

Solution steps

\int_{- 1}^{1} 6 y^{2} - 5 y^{4} d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 6 y^{2} d y - \int_{- 1}^{1} 5 y^{4} d y

\int_{- 1}^{1} 6 y^{2} d y = 4

\int_{- 1}^{1} 5 y^{4} d y = 2

= 4 - 2

Simplify

= 2

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What is the integral from-1 to 1 of (6y^2-5y^4) ?
The integral from-1 to 1 of (6y^2-5y^4) is 2