What is the integral from-2 to 3 of [te^t] ?

The integral from-2 to 3 of [te^t] is 2e^3+3/(e^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-2 to 3 of [te^t]

\int_{- 2}^{3} [t e^{t}] d t

2 e^{3} + \frac{3}{e ^{2}}

Decimal Notation

40.57707 \dots

Solution steps

\int_{- 2}^{3} t e^{t} d t

Apply Integration By Parts

: [e^{t} t - \int e^{t} d t]_{- 2}^{3}

= [e^{t} t - \int e^{t} d t]_{- 2}^{3}

\int e^{t} d t = e^{t}

= [e^{t} t - e^{t}]_{- 2}^{3}

Compute the boundaries:

2 e^{3} + \frac{3}{e ^{2}}

= 2 e^{3} + \frac{3}{e ^{2}}

\int_{1}^{4} (4 x^{5} - 6 x^{2} - 7 x + 3) d x

\int_{0}^{6} 2 x x^{2} + 1 d x

\int_{0}^{3 π} e^{t} 6 d t

\int_{0}^{2} 4 x^{2} - 8 x + 5 d x

What is the integral from-2 to 3 of [te^t] ?
The integral from-2 to 3 of [te^t] is 2e^3+3/(e^2)