What is the integral from 0 to pi/2 of (x+1)cos(x) ?

The integral from 0 to pi/2 of (x+1)cos(x) is pi/2

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integral from 0 to pi/2 of (x+1)cos(x)

\int_{0}^{\frac{π}{2}} (x + 1) cos (x) d x

\frac{π}{2}

Decimal Notation

1.57079 \dots

Solution steps

\int_{0}^{\frac{π}{2}} (x + 1) cos (x) d x

Apply Integration By Parts

: [sin (x) (x + 1) - \int sin (x) d x]_{0}^{\frac{π}{2}}

= [sin (x) (x + 1) - \int sin (x) d x]_{0}^{\frac{π}{2}}

\int sin (x) d x = - cos (x)

= [sin (x) (x + 1) - (- cos (x))]_{0}^{\frac{π}{2}}

Simplify

= [sin (x) (x + 1) + cos (x)]_{0}^{\frac{π}{2}}

Compute the boundaries:

\frac{π}{2}

= \frac{π}{2}

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What is the integral from 0 to pi/2 of (x+1)cos(x) ?
The integral from 0 to pi/2 of (x+1)cos(x) is pi/2