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Popular >

integral of (1+t)

Solution

\int (1 + t) d t

Solution

t + \frac{t ^{2}}{2} + C

Solution steps

\int 1 + t d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d t + \int t d t

\int 1 d t = t

\int t d t = \frac{t ^{2}}{2}

= t + \frac{t ^{2}}{2}

Add a constant to the solution

= t + \frac{t ^{2}}{2} + C

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Frequently Asked Questions (FAQ)

What is the integral of (1+t) ?
The integral of (1+t) is t+(t^2)/2+C