What is the integral from 1 to 27 of \sqrt[3]{x} ?

The integral from 1 to 27 of \sqrt[3]{x} is 60

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integral from 1 to 27 of \sqrt[3]{x}

\int_{1}^{27} 3 x d x

60

Solution steps

\int_{1}^{27} 3 x d x

Apply the Power Rule

: [\frac{3}{4} x^{\frac{4}{3}}]_{1}^{27}

= [\frac{3}{4} x^{\frac{4}{3}}]_{1}^{27}

Compute the boundaries:

60

= 60

x \to 4 lim (\frac{1}{( x - 4 ) ^{3}})

\int 2 x sec (x) tan (x) d x

\frac{d}{d x} (4 sin^{2} (x) + 9 cos^{2} (x))

\frac{\partial}{\partial x} (z^{2} x y)

\frac{d}{d t} (x^{2} + 3)

What is the integral from 1 to 27 of \sqrt[3]{x} ?
The integral from 1 to 27 of \sqrt[3]{x} is 60