What is the integral from-infinity to 3 of 1/(x^2-1) ?

The integral from-infinity to 3 of 1/(x^2-1) is diverges

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integral from-infinity to 3 of 1/(x^2-1)

\int_{- \infty}^{3} \frac{1}{x ^{2} - 1} d x

diverges

Solution steps

\int_{- \infty}^{3} \frac{1}{x ^{2} - 1} d x

Adjust integral based on undefined pointsThere are undefined points within the boundaries at

: - 1, 1

= \int_{- \infty}^{- 1} \frac{1}{x ^{2} - 1} d x + \int_{- 1}^{1} \frac{1}{x ^{2} - 1} d x + \int_{1}^{3} \frac{1}{x ^{2} - 1} d x

\int_{- \infty}^{- 1} \frac{1}{x ^{2} - 1} d x =

diverges

= diverges

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What is the integral from-infinity to 3 of 1/(x^2-1) ?
The integral from-infinity to 3 of 1/(x^2-1) is diverges