What is the integral from 0.8 to 1 of 1.25(1-x^4) ?

The integral from 0.8 to 1 of 1.25(1-x^4) is 0.08192

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integral from 0.8 to 1 of 1.25(1-x^4)

\int_{0.8}^{1} 1.25 (1 - x^{4}) d x

0.08192

Solution steps

\int_{0.8}^{1} 1.25 (1 - x^{4}) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 1.25 \cdot \int_{0.8}^{1} 1 - x^{4} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 1.25 (\int_{0.8}^{1} 1 d x - \int_{0.8}^{1} x^{4} d x)

\int_{0.8}^{1} 1 d x = 0.2

\int_{0.8}^{1} x^{4} d x = 0.134464

= 1.25 (0.2 - 0.134464)

Simplify

= 0.08192

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What is the integral from 0.8 to 1 of 1.25(1-x^4) ?
The integral from 0.8 to 1 of 1.25(1-x^4) is 0.08192