What is the integral from 0 to 3 of sin(x+1) ?

The integral from 0 to 3 of sin(x+1) is -cos(4)+cos(1)

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integral from 0 to 3 of sin(x+1)

\int_{0}^{3} sin (x + 1) d x

- cos (4) + cos (1)

Decimal

1.19394 \dots

Solution steps

\int_{0}^{3} sin (x + 1) d x

Apply u-substitution

= \int_{1}^{4} sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= [- cos (u)]_{1}^{4}

Compute the boundaries:

- cos (4) + cos (1)

= - cos (4) + cos (1)

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What is the integral from 0 to 3 of sin(x+1) ?
The integral from 0 to 3 of sin(x+1) is -cos(4)+cos(1)