What is the integral from-5 to-1 of 1/16 ?

The integral from-5 to-1 of 1/16 is 1/4

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integral from-5 to-1 of 1/16

\int_{- 5}^{- 1} \frac{1}{16} d x

\frac{1}{4}

Decimal Notation

0.25

Solution steps

\int_{- 5}^{- 1} \frac{1}{16} d x

Integral of a constant:

\int a d x = a x

= [\frac{1}{16} x]_{- 5}^{- 1}

Compute the boundaries:

\frac{1}{4}

= \frac{1}{4}

\int_{0}^{\frac{π}{2}} e^{- s t} sin (t) d t

\int_{0}^{5} (x^{2} + 4) d x

\int_{1}^{2} (x - 4) d x

\int_{- π}^{π} sin (2 x) cos (x) d x

\int_{1}^{2} [\frac{ln ( x )}{x ^{2}}] d x

What is the integral from-5 to-1 of 1/16 ?
The integral from-5 to-1 of 1/16 is 1/4