What is the integral from 4 to infinity of xe^{-x^2} ?

The integral from 4 to infinity of xe^{-x^2} is 1/(2e^{16)}

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integral from 4 to infinity of xe^{-x^2}

\int_{4}^{\infty} x e^{- x^{2}} d x

\frac{1}{2 e ^{16}}

Decimal Notation

5.62676 E - 8

Solution steps

\int_{4}^{\infty} x e^{- x^{2}} d x

Compute the indefinite integral:

\int x e^{- x^{2}} d x = - \frac{1}{2} e^{- x^{2}} + C

Compute the boundaries:

\int_{4}^{\infty} x e^{- x^{2}} d x = 0 - (- \frac{1}{2 e ^{16}})

= 0 - (- \frac{1}{2 e ^{16}})

Simplify

= \frac{1}{2 e ^{16}}

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What is the integral from 4 to infinity of xe^{-x^2} ?
The integral from 4 to infinity of xe^{-x^2} is 1/(2e^{16)}