What is the integral from 100 to 200 of-0.0003x^2+5x ?

The integral from 100 to 200 of-0.0003x^2+5x is 74300

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integral from 100 to 200 of-0.0003x^2+5x

\int_{100}^{200} - 0.0003 x^{2} + 5 x d x

74300

Solution steps

\int_{100}^{200} - 0.0003 x^{2} + 5 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{100}^{200} 0.0003 x^{2} d x + \int_{100}^{200} 5 x d x

\int_{100}^{200} 0.0003 x^{2} d x = 699.99999 \dots

\int_{100}^{200} 5 x d x = 75000

= - 699.99999 \dots + 75000

Simplify

= 74300

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What is the integral from 100 to 200 of-0.0003x^2+5x ?
The integral from 100 to 200 of-0.0003x^2+5x is 74300