What is the integral from 0 to sin(y) of y ?

The integral from 0 to sin(y) of y is 1/2 sin^2(y)

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integral from 0 to sin(y) of y

\int_{0}^{s i n (y)} y d y

\frac{1}{2} sin^{2} (y)

Solution steps

\int_{0}^{s i n (y)} y d y

Apply the Power Rule

: [\frac{y ^{2}}{2}]_{0}^{s i n (y)}

= [\frac{y ^{2}}{2}]_{0}^{s i n (y)}

Compute the boundaries:

\frac{1}{2} sin^{2} (y)

= \frac{1}{2} sin^{2} (y)

\int_{0}^{\frac{π}{2}} 8 cos (x) sin (sin (x)) d x

\int_{π}^{6 π} 9 cos (2 x) d x

\int_{2}^{3} e^{- x^{2}} d x

\int_{0}^{1} \frac{5 x}{( 2 x + 1 ) ^{3}} d x

\int_{1}^{2} \frac{8}{3} x^{3} y d y

What is the integral from 0 to sin(y) of y ?
The integral from 0 to sin(y) of y is 1/2 sin^2(y)