What is the integral from (-pi)/2 to pi/2 of sin(θ) ?

The integral from (-pi)/2 to pi/2 of sin(θ) is 0

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integral from (-pi)/2 to pi/2 of sin(θ)

\int_{\frac{- π}{2}}^{\frac{π}{2}} sin (θ) d θ

0

Solution steps

\int_{\frac{- π}{2}}^{\frac{π}{2}} sin (θ) d θ

Use the common integral:

\int sin (θ) d θ = - cos (θ)

= [- cos (θ)]_{\frac{- π}{2}}^{\frac{π}{2}}

Simplify

= [- cos (θ)]_{- \frac{π}{2}}^{\frac{π}{2}}

Compute the boundaries:

0

= 0

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What is the integral from (-pi)/2 to pi/2 of sin(θ) ?
The integral from (-pi)/2 to pi/2 of sin(θ) is 0