What is the integral from 1 to 3 of (4x-3-x^2) ?

The integral from 1 to 3 of (4x-3-x^2) is 4/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 3 of (4x-3-x^2)

\int_{1}^{3} (4 x - 3 - x^{2}) d x

\frac{4}{3}

Decimal Notation

1.33333 \dots

Solution steps

\int_{1}^{3} 4 x - 3 - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} 4 x d x - \int_{1}^{3} 3 d x - \int_{1}^{3} x^{2} d x

\int_{1}^{3} 4 x d x = 16

\int_{1}^{3} 3 d x = 6

\int_{1}^{3} x^{2} d x = \frac{26}{3}

= 16 - 6 - \frac{26}{3}

Simplify

16 - 6 - \frac{26}{3} : \frac{4}{3}

= \frac{4}{3}

\int_{- 6}^{- 3} \frac{1}{x + 2} d x

\int_{0.75}^{0.9} 3 x^{2} d x

\int_{1}^{l n (2)} x e^{4 x} d x

\int_{0}^{6} 2 x 4 x + 1 d x

\int_{0}^{1} (- 1 + \frac{π x}{2}) d x

What is the integral from 1 to 3 of (4x-3-x^2) ?
The integral from 1 to 3 of (4x-3-x^2) is 4/3