What is the limit as x approaches 2 of 2x^2+7x-1 ?

The limit as x approaches 2 of 2x^2+7x-1 is 21

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limit as x approaches 2 of 2x^2+7x-1

x \to 2 lim (2 x^{2} + 7 x - 1)

21

Solution steps

x \to 2 lim (2 x^{2} + 7 x - 1)

Plug in the value

x = 2

= 2 \cdot 2^{2} + 7 \cdot 2 - 1

Simplify

2 \cdot 2^{2} + 7 \cdot 2 - 1 : 21

= 21

x \to - 3 + lim (2 x^{2} - 6)

\frac{\partial}{\partial x} (x^{m})

\frac{\partial}{\partial x} (\frac{( 5 x + 3 )}{( y - 2 )})

x \to 5 lim (\frac{2 ^{x} - 32}{x - 5})

\frac{\partial}{\partial t} (t e^{\frac{s}{t}})

What is the limit as x approaches 2 of 2x^2+7x-1 ?
The limit as x approaches 2 of 2x^2+7x-1 is 21