What is the limit as x approaches 5 of (2^x-32)/(x-5) ?

The limit as x approaches 5 of (2^x-32)/(x-5) is 32ln(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 5 of (2^x-32)/(x-5)

x \to 5 lim (\frac{2 ^{x} - 32}{x - 5})

32 ln (2)

Decimal Notation

22.18070 \dots

Solution steps

x \to 5 lim (\frac{2 ^{x} - 32}{x - 5})

Apply L'Hopital's Rule

: x \to 5 lim (\frac{ln ( 2 ) \cdot 2 ^{x}}{1})

= x \to 5 lim (\frac{ln ( 2 ) \cdot 2 ^{x}}{1})

Plug in the value

x = 5

= \frac{ln ( 2 ) \cdot 2 ^{5}}{1}

Simplify

= 32 ln (2)

\frac{\partial}{\partial t} (t e^{\frac{s}{t}})

(t + 7)^{2}

x \to \infty lim (x + 0)

e^{x + 1}

\frac{d}{d x} (arctan (\frac{1 + x}{1 - x}))

What is the limit as x approaches 5 of (2^x-32)/(x-5) ?
The limit as x approaches 5 of (2^x-32)/(x-5) is 32ln(2)