What is the integral from 0 to 2 of (6x^2+4x+2) ?

The integral from 0 to 2 of (6x^2+4x+2) is 28

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2 of (6x^2+4x+2)

\int_{0}^{2} (6 x^{2} + 4 x + 2) d x

28

Solution steps

\int_{0}^{2} 6 x^{2} + 4 x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 6 x^{2} d x + \int_{0}^{2} 4 x d x + \int_{0}^{2} 2 d x

\int_{0}^{2} 6 x^{2} d x = 16

\int_{0}^{2} 4 x d x = 8

\int_{0}^{2} 2 d x = 4

= 16 + 8 + 4

Simplify

= 28

\int_{- 3}^{3} (x^{2} - 5 x + 1) d x

\int_{0}^{1} e^{y^{3}} y^{2} d y

\int_{2}^{2} cos (e^{t} + ln (t)) d t

\int_{0}^{1} \frac{x}{x ^{4} + 1} d x

\int_{2}^{5} (3 - ∣ x - 4 ∣) d x

What is the integral from 0 to 2 of (6x^2+4x+2) ?
The integral from 0 to 2 of (6x^2+4x+2) is 28