What is the integral from 0 to 2 of 9/5 x ?

The integral from 0 to 2 of 9/5 x is 18/5

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integral from 0 to 2 of 9/5 x

\int_{0}^{2} \frac{9}{5} x d x

\frac{18}{5}

Decimal Notation

3.6

Solution steps

\int_{0}^{2} \frac{9}{5} x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{9}{5} \cdot \int_{0}^{2} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{2}

= \frac{9}{5} [\frac{x ^{2}}{2}]_{0}^{2}

Compute the boundaries:

2

= \frac{9}{5} \cdot 2

Simplify

= \frac{18}{5}

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What is the integral from 0 to 2 of 9/5 x ?
The integral from 0 to 2 of 9/5 x is 18/5