What is the sum from n=0 to infinity of ((e^n))/5 ?

The sum from n=0 to infinity of ((e^n))/5 is diverges

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sum from n=0 to infinity of ((e^n))/5

n = 0 \sum \infty \frac{( e ^{n} )}{5}

diverges

Solution steps

n = 0 \sum \infty \frac{e ^{n}}{5}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= \frac{1}{5} \cdot n = 0 \sum \infty e^{n}

Apply Series Geometric Test:

diverges

= \frac{1}{5} diverges

= diverges

\frac{d}{d x} (- 8 x^{3})

\int_{\frac{1}{7}}^{5} 6 x ln (7 x) d x

\frac{d}{d x} (\frac{8}{x - 3})

x \to \frac{π}{2} lim (x \cdot sec (x))

x y^{^{'}} + 2 y = 0

What is the sum from n=0 to infinity of ((e^n))/5 ?
The sum from n=0 to infinity of ((e^n))/5 is diverges