What is the integral from 2 to 6 of 1/(sqrt(x)) ?

The integral from 2 to 6 of 1/(sqrt(x)) is 2sqrt(6)-2sqrt(2)

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integral from 2 to 6 of 1/(sqrt(x))

\int_{2}^{6} \frac{1}{x} d x

26 - 22

Decimal Notation

2.07055 \dots

Solution steps

\int_{2}^{6} \frac{1}{x} d x

Apply the Power Rule

: [2 x^{\frac{1}{2}}]_{2}^{6}

= [2 x^{\frac{1}{2}}]_{2}^{6}

Apply radical rule:

= [2 x]_{2}^{6}

Compute the boundaries:

26 - 22

= 26 - 22

\int_{0}^{1} 2 e^{6 x - 1} d x

\int_{10}^{x} \frac{- 1}{75} (x - 20) d x

\int_{- 2}^{2} x^{2} - x d x

\int_{1}^{2} x - 2 d x

\int_{0}^{1} (e^{- x})^{2} d x

What is the integral from 2 to 6 of 1/(sqrt(x)) ?
The integral from 2 to 6 of 1/(sqrt(x)) is 2sqrt(6)-2sqrt(2)