What is the integral from 1 to 2 of sqrt(x-2) ?

The integral from 1 to 2 of sqrt(x-2) is (2i)/3

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integral from 1 to 2 of sqrt(x-2)

\int_{1}^{2} x - 2 d x

\frac{2 i}{3}

Solution steps

\int_{1}^{2} x - 2 d x

Apply u-substitution

: \int_{- 1}^{0} u d u

= \int_{- 1}^{0} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{- 1}^{0}

= [\frac{2}{3} u^{\frac{3}{2}}]_{- 1}^{0}

Compute the boundaries:

i \frac{2}{3}

= i \frac{2}{3}

Simplify

= \frac{2 i}{3}

\int_{0}^{1} (e^{- x})^{2} d x

\int_{0}^{1} (3 x^{2} - 1) d x

\int_{- 1}^{\infty} 3 e^{- 4 x} d x

\int_{0}^{1} \frac{4}{2 x + 3} d x

\int_{0}^{a} y a^{2} - y^{2} d y

What is the integral from 1 to 2 of sqrt(x-2) ?
The integral from 1 to 2 of sqrt(x-2) is (2i)/3