What is the integral from-1 to infinity of 3e^{-4x} ?

The integral from-1 to infinity of 3e^{-4x} is (3e^4)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to infinity of 3e^{-4x}

\int_{- 1}^{\infty} 3 e^{- 4 x} d x

\frac{3 e ^{4}}{4}

Decimal

40.94861 \dots

Solution steps

\int_{- 1}^{\infty} 3 e^{- 4 x} d x

Compute the indefinite integral:

\int 3 e^{- 4 x} d x = - \frac{3}{4} e^{- 4 x} + C

Compute the boundaries:

\int_{- 1}^{\infty} 3 e^{- 4 x} d x = 0 - (- e^{4} \frac{3}{4})

= 0 - (- e^{4} \frac{3}{4})

Simplify

= \frac{3 e ^{4}}{4}

\int_{0}^{1} \frac{4}{2 x + 3} d x

\int_{0}^{a} y a^{2} - y^{2} d y

\int_{\frac{π}{6}}^{\frac{5 π}{6}} sin (x) d x

\int_{- 3}^{3} (3 x^{3} - 2 x^{2} + x + 1) d x

\int_{- \infty}^{4} 3 e^{- 3 x} d x

What is the integral from-1 to infinity of 3e^{-4x} ?
The integral from-1 to infinity of 3e^{-4x} is (3e^4)/4