What is the integral from 1500 to 2500 of k/(x^3) ?

The integral from 1500 to 2500 of k/(x^3) is k/(7031250)

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integral from 1500 to 2500 of k/(x^3)

\int_{1500}^{2500} \frac{k}{x ^{3}} d x

\frac{k}{7031250}

Solution steps

\int_{1500}^{2500} \frac{k}{x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= k \cdot \int_{1500}^{2500} \frac{1}{x ^{3}} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{1500}^{2500}

= k [- \frac{1}{2 x ^{2}}]_{1500}^{2500}

Compute the boundaries:

\frac{1}{7031250}

= k \frac{1}{7031250}

Simplify

= \frac{k}{7031250}

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What is the integral from 1500 to 2500 of k/(x^3) ?
The integral from 1500 to 2500 of k/(x^3) is k/(7031250)