What is the integral from 2.5 to 3 of (-x^2+4) ?

The integral from 2.5 to 3 of (-x^2+4) is -1.79166…

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integral from 2.5 to 3 of (-x^2+4)

\int_{2.5}^{3} (- x^{2} + 4) d x

- 1.79166 \dots

Solution steps

\int_{2.5}^{3} - x^{2} + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{2.5}^{3} x^{2} d x + \int_{2.5}^{3} 4 d x

\int_{2.5}^{3} x^{2} d x = 3.79166 \dots

\int_{2.5}^{3} 4 d x = 2

= - 3.79166 \dots + 2

Simplify

= - 1.79166 \dots

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What is the integral from 2.5 to 3 of (-x^2+4) ?
The integral from 2.5 to 3 of (-x^2+4) is -1.79166…