What is the integral from-3 to 4 of \sqrt[3]{5-x} ?

The integral from-3 to 4 of \sqrt[3]{5-x} is 45/4

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integral from-3 to 4 of \sqrt[3]{5-x}

\frac{45}{4}

Decimal Notation

11.25

Solution steps

Apply u-substitution

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply the Power Rule

: [\frac{3}{4} u^{\frac{4}{3}}]_{1}^{8}

= - (- [\frac{3}{4} u^{\frac{4}{3}}]_{1}^{8})

Simplify

= [\frac{3}{4} u^{\frac{4}{3}}]_{1}^{8}

Compute the boundaries:

\frac{45}{4}

= \frac{45}{4}

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What is the integral from-3 to 4 of \sqrt[3]{5-x} ?
The integral from-3 to 4 of \sqrt[3]{5-x} is 45/4