What is the integral from-1 to 3 of (x^{2/3}+1) ?

The integral from-1 to 3 of (x^{2/3}+1) is (9*3^{2/3}+3)/5+4

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integral from-1 to 3 of (x^{2/3}+1)

\int_{- 1}^{3} (x^{\frac{2}{3}} + 1) d x

\frac{9 \cdot 3 ^{\frac{2}{3}} + 3}{5} + 4

Decimal Notation

8.34415 \dots

Solution steps

\int_{- 1}^{3} x^{\frac{2}{3}} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{3} x^{\frac{2}{3}} d x + \int_{- 1}^{3} 1 d x

\int_{- 1}^{3} x^{\frac{2}{3}} d x = \frac{9 \cdot 3 ^{\frac{2}{3}} + 3}{5}

\int_{- 1}^{3} 1 d x = 4

= \frac{9 \cdot 3 ^{\frac{2}{3}} + 3}{5} + 4

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What is the integral from-1 to 3 of (x^{2/3}+1) ?
The integral from-1 to 3 of (x^{2/3}+1) is (9*3^{2/3}+3)/5+4