What is the integral from 0 to 2 of 1/(sqrt(y)) ?

The integral from 0 to 2 of 1/(sqrt(y)) is 2sqrt(2)

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integral from 0 to 2 of 1/(sqrt(y))

\int_{0}^{2} \frac{1}{y} d y

22

Decimal

2.82842 \dots

Solution steps

\int_{0}^{2} \frac{1}{y} d y

Apply the Power Rule

: [2 y^{\frac{1}{2}}]_{0}^{2}

= [2 y^{\frac{1}{2}}]_{0}^{2}

Apply radical rule:

a^{\frac{1}{n}} = n a

= [2 y]_{0}^{2}

Compute the boundaries:

22

= 22

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What is the integral from 0 to 2 of 1/(sqrt(y)) ?
The integral from 0 to 2 of 1/(sqrt(y)) is 2sqrt(2)