What is the integral from 0 to 0.8 of xe^x ?

The integral from 0 to 0.8 of xe^x is 0.55489…

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integral from 0 to 0.8 of xe^x

\int_{0}^{0.8} x e^{x} d x

0.55489 \dots

Solution steps

\int_{0}^{0.8} x e^{x} d x

Apply Integration By Parts

: [e^{x} x - \int e^{x} d x]_{0}^{0.8}

= [e^{x} x - \int e^{x} d x]_{0}^{0.8}

\int e^{x} d x = e^{x}

= [e^{x} x - e^{x}]_{0}^{0.8}

Compute the boundaries:

0.55489 \dots

= 0.55489 \dots

\int_{0}^{1} (\frac{1}{1 + x}) d x

\int_{0}^{1} \frac{32}{x ^{2} - 16} d x

\int_{1}^{2} \frac{x + 2}{x + 3} d x

\int_{- 7}^{6} - 2 y^{3} - y^{2} + 36 d y

\int_{0}^{1} 1 - x^{2} + \frac{x ^{4}}{2} d x

What is the integral from 0 to 0.8 of xe^x ?
The integral from 0 to 0.8 of xe^x is 0.55489…