What is the integral of (5x^4)/(x^5-3) ?

The integral of (5x^4)/(x^5-3) is ln|x^5-3|+C

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integral of (5x^4)/(x^5-3)

\int \frac{5 x ^{4}}{x ^{5} - 3} d x

ln x^{5} - 3 + C

Solution steps

\int \frac{5 x ^{4}}{x ^{5} - 3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int \frac{x ^{4}}{x ^{5} - 3} d x

Apply u-substitution

: \int \frac{1}{5 u} d u

= 5 \cdot \int \frac{1}{5 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \frac{1}{5} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= 5 \cdot \frac{1}{5} ln ∣ u ∣

Substitute back

u = x^{5} - 3

= 5 \cdot \frac{1}{5} ln x^{5} - 3

Simplify

5 \cdot \frac{1}{5} ln x^{5} - 3 : ln x^{5} - 3

= ln x^{5} - 3

Add a constant to the solution

= ln x^{5} - 3 + C

n = 1 \sum \infty \frac{1}{2 n}

y = x^{2} - 4, y = - 2 x

\frac{d}{d x} (e^{\frac{x ^{3}}{3}})

\int \frac{tan ^{3} ( \frac{8}{z} )}{z ^{2}} d z

\int \frac{x ^{2}}{x ^{2} - 4} d x

What is the integral of (5x^4)/(x^5-3) ?
The integral of (5x^4)/(x^5-3) is ln|x^5-3|+C