What is the integral from 0 to pi/2 of e^{-x}cos(x) ?

The integral from 0 to pi/2 of e^{-x}cos(x) is 1/(2e^{pi/2)}+1/2

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integral from 0 to pi/2 of e^{-x}cos(x)

\int_{0}^{\frac{π}{2}} e^{- x} cos (x) d x

\frac{1}{2 e ^{\frac{π}{2}}} + \frac{1}{2}

Decimal

0.60393 \dots

Solution steps

\int_{0}^{\frac{π}{2}} e^{- x} cos (x) d x

Compute the indefinite integral:

\int e^{- x} cos (x) d x = \frac{e ^{- x} sin ( x )}{2} - \frac{e ^{- x} cos ( x )}{2} + C

Compute the boundaries:

\int_{0}^{\frac{π}{2}} e^{- x} cos (x) d x = \frac{1}{2 e ^{\frac{π}{2}}} - (- \frac{1}{2})

= \frac{1}{2 e ^{\frac{π}{2}}} - (- \frac{1}{2})

Simplify

= \frac{1}{2 e ^{\frac{π}{2}}} + \frac{1}{2}

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What is the integral from 0 to pi/2 of e^{-x}cos(x) ?
The integral from 0 to pi/2 of e^{-x}cos(x) is 1/(2e^{pi/2)}+1/2