What is the integral from 3 to 6 of sqrt(x-2) ?

The integral from 3 to 6 of sqrt(x-2) is 14/3

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integral from 3 to 6 of sqrt(x-2)

\int_{3}^{6} x - 2 d x

\frac{14}{3}

Decimal Notation

4.66666 \dots

Solution steps

\int_{3}^{6} x - 2 d x

Apply u-substitution

: \int_{1}^{4} u d u

= \int_{1}^{4} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{1}^{4}

= [\frac{2}{3} u^{\frac{3}{2}}]_{1}^{4}

Compute the boundaries:

\frac{14}{3}

= \frac{14}{3}

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What is the integral from 3 to 6 of sqrt(x-2) ?
The integral from 3 to 6 of sqrt(x-2) is 14/3