What is the integral from 1 to 16 of x^{3/2} ?

The integral from 1 to 16 of x^{3/2} is 2046/5

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integral from 1 to 16 of x^{3/2}

\int_{1}^{16} x^{\frac{3}{2}} d x

\frac{2046}{5}

Decimal Notation

409.2

Solution steps

\int_{1}^{16} x^{\frac{3}{2}} d x

Apply the Power Rule

: [\frac{2}{5} x^{\frac{5}{2}}]_{1}^{16}

= [\frac{2}{5} x^{\frac{5}{2}}]_{1}^{16}

Compute the boundaries:

\frac{2046}{5}

= \frac{2046}{5}

\int_{0}^{2} [x^{2}] d x

\int_{1}^{2} \frac{1}{( 5 - 2 x ) ^{2}} d x

\int_{0}^{4} (30 - x) d x

\int_{0}^{4} (x - 4)^{3} d x

\int_{0}^{2} x^{2} - 6 x + 8 d x

What is the integral from 1 to 16 of x^{3/2} ?
The integral from 1 to 16 of x^{3/2} is 2046/5