What is the solution for (dx)/(dt)=4x-x^3 ?

The solution for (dx)/(dt)=4x-x^3 is x= 2/(sqrt(-e^{-8t-c_{1))+1}},x=-2/(sqrt(-e^{-8t-c_{1))+1}}

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(dx)/(dt)=4x-x^3

\frac{d x}{d t} = 4 x - x^{3}

x = \frac{2}{- e ^{- 8 t - c_{1}} + 1}, x = - \frac{2}{- e ^{- 8 t - c_{1}} + 1}

Solution steps

\frac{d x}{d t} = 4 x - x^{3}

Solve Bernoulli ODE:

x = \frac{2}{- e ^{- 8 t - c_{1}} + 1}, x = - \frac{2}{- e ^{- 8 t - c_{1}} + 1}

x = \frac{2}{- e ^{- 8 t - c_{1}} + 1}, x = - \frac{2}{- e ^{- 8 t - c_{1}} + 1}

\int_{0}^{\infty} x^{2} e^{- 2 x} d x

\int \frac{9 x ^{2}}{4 x - x ^{2}} d x

f (x) = 3 x + 91, (3, 10)

\int cos^{5} (x) sin^{6} (x) d x

y = 101.57 e^{0.328 x}

What is the solution for (dx)/(dt)=4x-x^3 ?
The solution for (dx)/(dt)=4x-x^3 is x= 2/(sqrt(-e^{-8t-c_{1))+1}},x=-2/(sqrt(-e^{-8t-c_{1))+1}}