What is the tangent of f(x)=sqrt(3x+91),(3,10) ?

The tangent of f(x)=sqrt(3x+91),(3,10) is y= 3/20 x+191/20

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=sqrt(3x+91),(3,10)

tangent of

f (x) = 3 x + 91, (3, 10)

y = \frac{3}{20} x + \frac{191}{20}

Solution steps

Find the slope of

f (x) = 3 x + 91 : \frac{df ( x )}{d x} = \frac{3}{2 3 x + 91}

Compute the slope of

f (x) = 3 x + 91

(3, 10) : m = \frac{3}{20}

Find the line with slope m=

\frac{3}{20}

and passing through

(3, 10) : y = \frac{3}{20} x + \frac{191}{20}

y = \frac{3}{20} x + \frac{191}{20}

\int cos^{5} (x) sin^{6} (x) d x

y = 101.57 e^{0.328 x}

\int \frac{x ^{2} - 6 x + 1}{x ^{2} + 1} d x

\frac{d}{d x} ((4 - x^{2})^{\frac{1}{2}})

\int_{0}^{\infty} 6 e^{- x} d x

What is the tangent of f(x)=sqrt(3x+91),(3,10) ?
The tangent of f(x)=sqrt(3x+91),(3,10) is y= 3/20 x+191/20