What is the integral from 0 to infinity of 6e^{-x} ?

The integral from 0 to infinity of 6e^{-x} is 6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to infinity of 6e^{-x}

\int_{0}^{\infty} 6 e^{- x} d x

6

Solution steps

\int_{0}^{\infty} 6 e^{- x} d x

Compute the indefinite integral:

\int 6 e^{- x} d x = - 6 e^{- x} + C

Compute the boundaries:

\int_{0}^{\infty} 6 e^{- x} d x = 0 - (- 6)

= 0 - (- 6)

Simplify

= 6

n = 0 \sum \infty (x - 9)^{n}

\frac{d}{d x} (2 + ln (x))

y^{^{'}} + 4 x y = x

\frac{d}{d x} (ln (1 + x^{4}))

\int_{4}^{\infty} e^{- \frac{y}{2}} d y

What is the integral from 0 to infinity of 6e^{-x} ?
The integral from 0 to infinity of 6e^{-x} is 6