What is the integral from sin(x) to cos(x) of 1 ?

The integral from sin(x) to cos(x) of 1 is cos(x)-sin(x)

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integral from sin(x) to cos(x) of 1

\int_{s i n (x)}^{c o s (x)} 1 d y

cos (x) - sin (x)

Solution steps

\int_{s i n (x)}^{c o s (x)} 1 d y

Integral of a constant:

\int a d x = a x

= [1 \cdot y]_{s i n (x)}^{c o s (x)}

Simplify

= [y]_{s i n (x)}^{c o s (x)}

Compute the boundaries:

cos (x) - sin (x)

= cos (x) - sin (x)

\int_{- 2}^{2} π (e^{x})^{2} d x

\int_{- 2}^{1} (2 x^{2} + 8) d x

\int_{- 1}^{1} (\frac{1}{3} + \frac{x ^{4}}{2}) d x

\int_{- \infty}^{0} x e^{3 x + 1} d x

\int_{0}^{\frac{π}{8}} sin^{3} (8 x) d x

What is the integral from sin(x) to cos(x) of 1 ?
The integral from sin(x) to cos(x) of 1 is cos(x)-sin(x)