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Popular >

y^'+4xy=x

Solution

y^{^{'}} + 4 x y = x

Solution

y = \frac{e ^{- 2 x^{2} + c_{1}}}{4} + \frac{1}{4}

Solution steps

y^{'} (x) + 4 x y = x

Solve separable ODE:

y = \frac{e ^{- 2 x^{2} + c_{1}}}{4} + \frac{1}{4}

y = \frac{e ^{- 2 x^{2} + c_{1}}}{4} + \frac{1}{4}

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Frequently Asked Questions (FAQ)

What is the solution for y^'+4xy=x ?
The solution for y^'+4xy=x is y=(e^{-2x^2+c_{1}})/4+1/4