What is the integral from-pi/2 to pi/2 of sin(t) ?

The integral from-pi/2 to pi/2 of sin(t) is 0

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integral from-pi/2 to pi/2 of sin(t)

\int_{- \frac{π}{2}}^{\frac{π}{2}} sin (t) d t

0

Solution steps

\int_{- \frac{π}{2}}^{\frac{π}{2}} sin (t) d t

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

sin (t) :

Odd

= 0

\int_{0}^{\frac{1}{2}} x^{4} d x

\int_{0}^{1} \frac{2 x}{x ^{2} + 4 x + 29} d x

\int_{- \infty}^{0} e^{17 x} d x

\int_{1}^{2} x^{2} (\frac{3}{7} x^{2}) d x

\int_{0}^{\frac{π}{2}} x^{3} \cdot cos (2 x) d x

What is the integral from-pi/2 to pi/2 of sin(t) ?
The integral from-pi/2 to pi/2 of sin(t) is 0