What is the integral from 1 to 7 of 1/(xln(x)) ?

The integral from 1 to 7 of 1/(xln(x)) is diverges

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integral from 1 to 7 of 1/(xln(x))

\int_{1}^{7} \frac{1}{x ln ( x )} d x

diverges

Solution steps

\int_{1}^{7} \frac{1}{x ln ( x )} d x

Apply u-substitution

: \int_{0}^{l n (7)} \frac{1}{u} d u

= \int_{0}^{l n (7)} \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= [ln ∣ u ∣]_{0}^{l n (7)}

Compute the boundaries:

diverges

= diverges

\int_{0}^{5} x^{2} - 4 d x

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\int_{1}^{4} (x)^{2} d x

\int_{0}^{2} (t + 2)^{2} - 3 d t

\int_{0}^{1} (\frac{y}{1 + x y}) d x

What is the integral from 1 to 7 of 1/(xln(x)) ?
The integral from 1 to 7 of 1/(xln(x)) is diverges