What is the integral from-1 to 1 of x/(sqrt(x^2+1)) ?

The integral from-1 to 1 of x/(sqrt(x^2+1)) is 0

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integral from-1 to 1 of x/(sqrt(x^2+1))

\int_{- 1}^{1} \frac{x}{x ^{2} + 1} d x

0

Solution steps

\int_{- 1}^{1} \frac{x}{x ^{2} + 1} d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

\frac{x}{x ^{2} + 1} :

Odd

= 0

\int_{- π}^{π} x \cdot cos (n x) d x

\int_{s}^{\infty} \frac{1}{s ^{2} + 1} d s

\int_{0}^{1} 11 ln (x) d x

\int_{0}^{t} 120 e^{- 10 t} d t

\int_{e}^{e^{2}} x^{2} ln (x) d x

What is the integral from-1 to 1 of x/(sqrt(x^2+1)) ?
The integral from-1 to 1 of x/(sqrt(x^2+1)) is 0