What is the integral from 0 to 3 of kx^2 ?

The integral from 0 to 3 of kx^2 is k*9

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integral from 0 to 3 of kx^2

\int_{0}^{3} k x^{2} d x

k \cdot 9

Solution steps

\int_{0}^{3} k x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= k \cdot \int_{0}^{3} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{3}

= k [\frac{x ^{3}}{3}]_{0}^{3}

Compute the boundaries:

9

= k \cdot 9

\int_{1}^{3} \frac{2}{x ^{2} - 1} d x

\int_{1}^{\infty} n e^{- n^{2}}

\int_{1}^{4} 5 x (x - 1) d x

\int_{0}^{1} y \cdot 2 y d y

\int_{1}^{2} \frac{1}{t - 1} d t

What is the integral from 0 to 3 of kx^2 ?
The integral from 0 to 3 of kx^2 is k*9