What is the derivative of x^3-6x^2 ?

The derivative of x^3-6x^2 is 3x^2-12x

What is the first derivative of x^3-6x^2 ?

The first derivative of x^3-6x^2 is 3x^2-12x

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\frac{d}{d x} (x^{3} - 6 x^{2})

3 x^{2} - 12 x

Solution steps

\frac{d}{d x} (x^{3} - 6 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (6 x^{2})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (6 x^{2}) = 12 x

= 3 x^{2} - 12 x

\frac{d x}{d t} = x^{2} + \frac{1}{36}

\frac{d}{d x} (x^{2} - x + 1)

y = x (2 x + 3)

\frac{d}{d x} (x (x + 1))

\frac{d}{d x} (ln (2 x y + 4))

What is the derivative of x^3-6x^2 ?
The derivative of x^3-6x^2 is 3x^2-12x
What is the first derivative of x^3-6x^2 ?
The first derivative of x^3-6x^2 is 3x^2-12x